Solve 8x + 1 = 49
The solution of 8x + 1 = 49 is x = 6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 8:
- 4
Check: put x = 6 back into the equation.
LaTeX source of the formulas on this page
\[ 8x + 1 = 49\ \Rightarrow\ x = 6 \]
\[ 8x + 1 = 49 \]
\[ 8x + 1 - 1 = 49 - 1 \ \Rightarrow\ 8x = 48 \]
\[ \frac{8x}{8} = \frac{48}{8} \ \Rightarrow\ x = 6 \]
\[ 8\cdot6 + 1 = 48 + 1 = 49 \checkmark \]Trying values of x in 8x + 1 = 49
| x | 8x + 1 | Equals 49? |
|---|---|---|
| 4 | 33 | no |
| 5 | 41 | no |
| 6 | 49 | yes |
| 7 | 57 | no |
| 8 | 65 | no |
Questions
What is x in 8x + 1 = 49?
The solution of 8x + 1 = 49 is x = 6.
How do you solve 8x + 1 = 49?
Subtract 1 from both sides to get 8x = 48, then divide both sides by 8 to get x = 6.
How do I check the answer?
Replace x by 6: 8(6) + 1 = 49, which is 49.