Solve 6x + 12 = ā48
The solution of 6x + 12 = ā48 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 6:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 6x + 12 = -48\ \Rightarrow\ x = -10 \]
\[ 6x + 12 = -48 \]
\[ 6x + 12 - 12 = -48 - 12 \ \Rightarrow\ 6x = -60 \]
\[ \frac{6x}{6} = \frac{-60}{6} \ \Rightarrow\ x = -10 \]
\[ 6\cdot(-10) + 12 = -60 + 12 = -48 \checkmark \]Trying values of x in 6x + 12 = ā48
| x | 6x + 12 | Equals -48? |
|---|---|---|
| -12 | -60 | no |
| -11 | -54 | no |
| -10 | -48 | yes |
| -9 | -42 | no |
| -8 | -36 | no |
Questions
What is x in 6x + 12 = ā48?
The solution of 6x + 12 = ā48 is x = -10.
How do you solve 6x + 12 = ā48?
Subtract 12 from both sides to get 6x = -60, then divide both sides by 6 to get x = -10.
How do I check the answer?
Replace x by -10: 6(-10) + 12 = -48, which is -48.