Solve 7x + 12 = ā58
The solution of 7x + 12 = ā58 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 7:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 7x + 12 = -58\ \Rightarrow\ x = -10 \]
\[ 7x + 12 = -58 \]
\[ 7x + 12 - 12 = -58 - 12 \ \Rightarrow\ 7x = -70 \]
\[ \frac{7x}{7} = \frac{-70}{7} \ \Rightarrow\ x = -10 \]
\[ 7\cdot(-10) + 12 = -70 + 12 = -58 \checkmark \]Trying values of x in 7x + 12 = ā58
| x | 7x + 12 | Equals -58? |
|---|---|---|
| -12 | -72 | no |
| -11 | -65 | no |
| -10 | -58 | yes |
| -9 | -51 | no |
| -8 | -44 | no |
Questions
What is x in 7x + 12 = ā58?
The solution of 7x + 12 = ā58 is x = -10.
How do you solve 7x + 12 = ā58?
Subtract 12 from both sides to get 7x = -70, then divide both sides by 7 to get x = -10.
How do I check the answer?
Replace x by -10: 7(-10) + 12 = -58, which is -58.