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Solve 7x + 12 = āˆ’58

The solution of 7x + 12 = āˆ’58 is x = -10.

The lines y = 7x + 12 and y = -58 meet at x = -10-16-14-12-10-8-6-4-100-80-60-40-20x = -10y = 7x + 12y = -58
The lines y = 7x + 12 and y = -58 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    7x+12=āˆ’587x + 12 = -58
  2. 2

    Subtract 12 from both sides:

    7x+12āˆ’12=āˆ’58āˆ’12 ⇒ 7x=āˆ’707x + 12 - 12 = -58 - 12 \ \Rightarrow\ 7x = -70
  3. 3

    Divide both sides by 7:

    7x7=āˆ’707 ⇒ x=āˆ’10\frac{7x}{7} = \frac{-70}{7} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    7ā‹…(āˆ’10)+12=āˆ’70+12=āˆ’58āœ“7\cdot(-10) + 12 = -70 + 12 = -58 \checkmark
LaTeX source of the formulas on this page
\[ 7x + 12 = -58\ \Rightarrow\ x = -10 \]
\[ 7x + 12 = -58 \]
\[ 7x + 12 - 12 = -58 - 12 \ \Rightarrow\ 7x = -70 \]
\[ \frac{7x}{7} = \frac{-70}{7} \ \Rightarrow\ x = -10 \]
\[ 7\cdot(-10) + 12 = -70 + 12 = -58 \checkmark \]

Trying values of x in 7x + 12 = āˆ’58

x7x + 12Equals -58?
-12-72no
-11-65no
-10-58yes
-9-51no
-8-44no

Questions

What is x in 7x + 12 = āˆ’58?

The solution of 7x + 12 = āˆ’58 is x = -10.

How do you solve 7x + 12 = āˆ’58?

Subtract 12 from both sides to get 7x = -70, then divide both sides by 7 to get x = -10.

How do I check the answer?

Replace x by -10: 7(-10) + 12 = -58, which is -58.

Similar equations

    Solve 7x + 12 = āˆ’58: x = -10 (steps and check) | WordGPT