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Solve 8x + 12 = āˆ’68

The solution of 8x + 12 = āˆ’68 is x = -10.

The lines y = 8x + 12 and y = -68 meet at x = -10-16-14-12-10-8-6-4-120-100-80-60-40-20x = -10y = 8x + 12y = -68
The lines y = 8x + 12 and y = -68 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    8x+12=āˆ’688x + 12 = -68
  2. 2

    Subtract 12 from both sides:

    8x+12āˆ’12=āˆ’68āˆ’12 ⇒ 8x=āˆ’808x + 12 - 12 = -68 - 12 \ \Rightarrow\ 8x = -80
  3. 3

    Divide both sides by 8:

    8x8=āˆ’808 ⇒ x=āˆ’10\frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    8ā‹…(āˆ’10)+12=āˆ’80+12=āˆ’68āœ“8\cdot(-10) + 12 = -80 + 12 = -68 \checkmark
LaTeX source of the formulas on this page
\[ 8x + 12 = -68\ \Rightarrow\ x = -10 \]
\[ 8x + 12 = -68 \]
\[ 8x + 12 - 12 = -68 - 12 \ \Rightarrow\ 8x = -80 \]
\[ \frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10 \]
\[ 8\cdot(-10) + 12 = -80 + 12 = -68 \checkmark \]

Trying values of x in 8x + 12 = āˆ’68

x8x + 12Equals -68?
-12-84no
-11-76no
-10-68yes
-9-60no
-8-52no

Questions

What is x in 8x + 12 = āˆ’68?

The solution of 8x + 12 = āˆ’68 is x = -10.

How do you solve 8x + 12 = āˆ’68?

Subtract 12 from both sides to get 8x = -80, then divide both sides by 8 to get x = -10.

How do I check the answer?

Replace x by -10: 8(-10) + 12 = -68, which is -68.

Similar equations

    Solve 8x + 12 = āˆ’68: x = -10 (steps and check) | WordGPT