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Solve 8x āˆ’ 12 = āˆ’92

The solution of 8x āˆ’ 12 = āˆ’92 is x = -10.

The lines y = 8x āˆ’ 12 and y = -92 meet at x = -10-16-14-12-10-8-6-4-140-120-100-80-60-40x = -10y = 8x āˆ’ 12y = -92
The lines y = 8x āˆ’ 12 and y = -92 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    8xāˆ’12=āˆ’928x - 12 = -92
  2. 2

    Add 12 to both sides:

    8xāˆ’12+12=āˆ’92+12 ⇒ 8x=āˆ’808x - 12 + 12 = -92 + 12 \ \Rightarrow\ 8x = -80
  3. 3

    Divide both sides by 8:

    8x8=āˆ’808 ⇒ x=āˆ’10\frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    8ā‹…(āˆ’10)āˆ’12=āˆ’80āˆ’12=āˆ’92āœ“8\cdot(-10) - 12 = -80 - 12 = -92 \checkmark
LaTeX source of the formulas on this page
\[ 8x - 12 = -92\ \Rightarrow\ x = -10 \]
\[ 8x - 12 = -92 \]
\[ 8x - 12 + 12 = -92 + 12 \ \Rightarrow\ 8x = -80 \]
\[ \frac{8x}{8} = \frac{-80}{8} \ \Rightarrow\ x = -10 \]
\[ 8\cdot(-10) - 12 = -80 - 12 = -92 \checkmark \]

Trying values of x in 8x āˆ’ 12 = āˆ’92

x8x āˆ’ 12Equals -92?
-12-108no
-11-100no
-10-92yes
-9-84no
-8-76no

Questions

What is x in 8x āˆ’ 12 = āˆ’92?

The solution of 8x āˆ’ 12 = āˆ’92 is x = -10.

How do you solve 8x āˆ’ 12 = āˆ’92?

Add 12 to both sides to get 8x = -80, then divide both sides by 8 to get x = -10.

How do I check the answer?

Replace x by -10: 8(-10) āˆ’ 12 = -92, which is -92.

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    Solve 8x āˆ’ 12 = āˆ’92: x = -10 (steps and check) | WordGPT