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Solve 6x āˆ’ 12 = āˆ’72

The solution of 6x āˆ’ 12 = āˆ’72 is x = -10.

The lines y = 6x āˆ’ 12 and y = -72 meet at x = -10-16-14-12-10-8-6-4-110-100-90-80-70-60-50-40-30x = -10y = 6x āˆ’ 12y = -72
The lines y = 6x āˆ’ 12 and y = -72 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    6xāˆ’12=āˆ’726x - 12 = -72
  2. 2

    Add 12 to both sides:

    6xāˆ’12+12=āˆ’72+12 ⇒ 6x=āˆ’606x - 12 + 12 = -72 + 12 \ \Rightarrow\ 6x = -60
  3. 3

    Divide both sides by 6:

    6x6=āˆ’606 ⇒ x=āˆ’10\frac{6x}{6} = \frac{-60}{6} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    6ā‹…(āˆ’10)āˆ’12=āˆ’60āˆ’12=āˆ’72āœ“6\cdot(-10) - 12 = -60 - 12 = -72 \checkmark
LaTeX source of the formulas on this page
\[ 6x - 12 = -72\ \Rightarrow\ x = -10 \]
\[ 6x - 12 = -72 \]
\[ 6x - 12 + 12 = -72 + 12 \ \Rightarrow\ 6x = -60 \]
\[ \frac{6x}{6} = \frac{-60}{6} \ \Rightarrow\ x = -10 \]
\[ 6\cdot(-10) - 12 = -60 - 12 = -72 \checkmark \]

Trying values of x in 6x āˆ’ 12 = āˆ’72

x6x āˆ’ 12Equals -72?
-12-84no
-11-78no
-10-72yes
-9-66no
-8-60no

Questions

What is x in 6x āˆ’ 12 = āˆ’72?

The solution of 6x āˆ’ 12 = āˆ’72 is x = -10.

How do you solve 6x āˆ’ 12 = āˆ’72?

Add 12 to both sides to get 6x = -60, then divide both sides by 6 to get x = -10.

How do I check the answer?

Replace x by -10: 6(-10) āˆ’ 12 = -72, which is -72.

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    Solve 6x āˆ’ 12 = āˆ’72: x = -10 (steps and check) | WordGPT