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Solve 3x + 1 = āˆ’20

The solution of 3x + 1 = āˆ’20 is x = -7.

The lines y = 3x + 1 and y = -20 meet at x = -7-12-10-8-6-4-2-40-35-30-25-20-15-10-5x = -7y = 3x + 1y = -20
The lines y = 3x + 1 and y = -20 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+1=āˆ’203x + 1 = -20
  2. 2

    Subtract 1 from both sides:

    3x+1āˆ’1=āˆ’20āˆ’1 ⇒ 3x=āˆ’213x + 1 - 1 = -20 - 1 \ \Rightarrow\ 3x = -21
  3. 3

    Divide both sides by 3:

    3x3=āˆ’213 ⇒ x=āˆ’7\frac{3x}{3} = \frac{-21}{3} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    3ā‹…(āˆ’7)+1=āˆ’21+1=āˆ’20āœ“3\cdot(-7) + 1 = -21 + 1 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 1 = -20\ \Rightarrow\ x = -7 \]
\[ 3x + 1 = -20 \]
\[ 3x + 1 - 1 = -20 - 1 \ \Rightarrow\ 3x = -21 \]
\[ \frac{3x}{3} = \frac{-21}{3} \ \Rightarrow\ x = -7 \]
\[ 3\cdot(-7) + 1 = -21 + 1 = -20 \checkmark \]

Trying values of x in 3x + 1 = āˆ’20

x3x + 1Equals -20?
-9-26no
-8-23no
-7-20yes
-6-17no
-5-14no

Questions

What is x in 3x + 1 = āˆ’20?

The solution of 3x + 1 = āˆ’20 is x = -7.

How do you solve 3x + 1 = āˆ’20?

Subtract 1 from both sides to get 3x = -21, then divide both sides by 3 to get x = -7.

How do I check the answer?

Replace x by -7: 3(-7) + 1 = -20, which is -20.

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    Solve 3x + 1 = āˆ’20: x = -7 (steps and check) | WordGPT