Solve 4x + 1 = ā27
The solution of 4x + 1 = ā27 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 1 = -27\ \Rightarrow\ x = -7 \]
\[ 4x + 1 = -27 \]
\[ 4x + 1 - 1 = -27 - 1 \ \Rightarrow\ 4x = -28 \]
\[ \frac{4x}{4} = \frac{-28}{4} \ \Rightarrow\ x = -7 \]
\[ 4\cdot(-7) + 1 = -28 + 1 = -27 \checkmark \]Trying values of x in 4x + 1 = ā27
| x | 4x + 1 | Equals -27? |
|---|---|---|
| -9 | -35 | no |
| -8 | -31 | no |
| -7 | -27 | yes |
| -6 | -23 | no |
| -5 | -19 | no |
Questions
What is x in 4x + 1 = ā27?
The solution of 4x + 1 = ā27 is x = -7.
How do you solve 4x + 1 = ā27?
Subtract 1 from both sides to get 4x = -28, then divide both sides by 4 to get x = -7.
How do I check the answer?
Replace x by -7: 4(-7) + 1 = -27, which is -27.