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Solve 3x + 1 = āˆ’17

The solution of 3x + 1 = āˆ’17 is x = -6.

The lines y = 3x + 1 and y = -17 meet at x = -6-12-10-8-6-4-2-35-30-25-20-15-10-5x = -6y = 3x + 1y = -17
The lines y = 3x + 1 and y = -17 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+1=āˆ’173x + 1 = -17
  2. 2

    Subtract 1 from both sides:

    3x+1āˆ’1=āˆ’17āˆ’1 ⇒ 3x=āˆ’183x + 1 - 1 = -17 - 1 \ \Rightarrow\ 3x = -18
  3. 3

    Divide both sides by 3:

    3x3=āˆ’183 ⇒ x=āˆ’6\frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    3ā‹…(āˆ’6)+1=āˆ’18+1=āˆ’17āœ“3\cdot(-6) + 1 = -18 + 1 = -17 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 1 = -17\ \Rightarrow\ x = -6 \]
\[ 3x + 1 = -17 \]
\[ 3x + 1 - 1 = -17 - 1 \ \Rightarrow\ 3x = -18 \]
\[ \frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6 \]
\[ 3\cdot(-6) + 1 = -18 + 1 = -17 \checkmark \]

Trying values of x in 3x + 1 = āˆ’17

x3x + 1Equals -17?
-8-23no
-7-20no
-6-17yes
-5-14no
-4-11no

Questions

What is x in 3x + 1 = āˆ’17?

The solution of 3x + 1 = āˆ’17 is x = -6.

How do you solve 3x + 1 = āˆ’17?

Subtract 1 from both sides to get 3x = -18, then divide both sides by 3 to get x = -6.

How do I check the answer?

Replace x by -6: 3(-6) + 1 = -17, which is -17.

Similar equations

    Solve 3x + 1 = āˆ’17: x = -6 (steps and check) | WordGPT