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Solve 3x āˆ’ 1 = āˆ’19

The solution of 3x āˆ’ 1 = āˆ’19 is x = -6.

The lines y = 3x āˆ’ 1 and y = -19 meet at x = -6-12-10-8-6-4-2-40-35-30-25-20-15-10-5x = -6y = 3x āˆ’ 1y = -19
The lines y = 3x āˆ’ 1 and y = -19 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’1=āˆ’193x - 1 = -19
  2. 2

    Add 1 to both sides:

    3xāˆ’1+1=āˆ’19+1 ⇒ 3x=āˆ’183x - 1 + 1 = -19 + 1 \ \Rightarrow\ 3x = -18
  3. 3

    Divide both sides by 3:

    3x3=āˆ’183 ⇒ x=āˆ’6\frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    3ā‹…(āˆ’6)āˆ’1=āˆ’18āˆ’1=āˆ’19āœ“3\cdot(-6) - 1 = -18 - 1 = -19 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 1 = -19\ \Rightarrow\ x = -6 \]
\[ 3x - 1 = -19 \]
\[ 3x - 1 + 1 = -19 + 1 \ \Rightarrow\ 3x = -18 \]
\[ \frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6 \]
\[ 3\cdot(-6) - 1 = -18 - 1 = -19 \checkmark \]

Trying values of x in 3x āˆ’ 1 = āˆ’19

x3x āˆ’ 1Equals -19?
-8-25no
-7-22no
-6-19yes
-5-16no
-4-13no

Questions

What is x in 3x āˆ’ 1 = āˆ’19?

The solution of 3x āˆ’ 1 = āˆ’19 is x = -6.

How do you solve 3x āˆ’ 1 = āˆ’19?

Add 1 to both sides to get 3x = -18, then divide both sides by 3 to get x = -6.

How do I check the answer?

Replace x by -6: 3(-6) āˆ’ 1 = -19, which is -19.

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    Solve 3x āˆ’ 1 = āˆ’19: x = -6 (steps and check) | WordGPT