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Solve 3x āˆ’ 1 = āˆ’16

The solution of 3x āˆ’ 1 = āˆ’16 is x = -5.

The lines y = 3x āˆ’ 1 and y = -16 meet at x = -5-10-8-6-4-2-35-30-25-20-15-10-55x = -5y = 3x āˆ’ 1y = -16
The lines y = 3x āˆ’ 1 and y = -16 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’1=āˆ’163x - 1 = -16
  2. 2

    Add 1 to both sides:

    3xāˆ’1+1=āˆ’16+1 ⇒ 3x=āˆ’153x - 1 + 1 = -16 + 1 \ \Rightarrow\ 3x = -15
  3. 3

    Divide both sides by 3:

    3x3=āˆ’153 ⇒ x=āˆ’5\frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    3ā‹…(āˆ’5)āˆ’1=āˆ’15āˆ’1=āˆ’16āœ“3\cdot(-5) - 1 = -15 - 1 = -16 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 1 = -16\ \Rightarrow\ x = -5 \]
\[ 3x - 1 = -16 \]
\[ 3x - 1 + 1 = -16 + 1 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) - 1 = -15 - 1 = -16 \checkmark \]

Trying values of x in 3x āˆ’ 1 = āˆ’16

x3x āˆ’ 1Equals -16?
-7-22no
-6-19no
-5-16yes
-4-13no
-3-10no

Questions

What is x in 3x āˆ’ 1 = āˆ’16?

The solution of 3x āˆ’ 1 = āˆ’16 is x = -5.

How do you solve 3x āˆ’ 1 = āˆ’16?

Add 1 to both sides to get 3x = -15, then divide both sides by 3 to get x = -5.

How do I check the answer?

Replace x by -5: 3(-5) āˆ’ 1 = -16, which is -16.

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    Solve 3x āˆ’ 1 = āˆ’16: x = -5 (steps and check) | WordGPT