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Solve 3x āˆ’ 12 = āˆ’12

The solution of 3x āˆ’ 12 = āˆ’12 is x = 0.

The lines y = 3x āˆ’ 12 and y = -12 meet at x = 0-6-4-2246-30-25-20-15-10-55x = 0y = 3x āˆ’ 12y = -12
The lines y = 3x āˆ’ 12 and y = -12 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’12=āˆ’123x - 12 = -12
  2. 2

    Add 12 to both sides:

    3xāˆ’12+12=āˆ’12+12 ⇒ 3x=03x - 12 + 12 = -12 + 12 \ \Rightarrow\ 3x = 0
  3. 3

    Divide both sides by 3:

    3x3=03 ⇒ x=0\frac{3x}{3} = \frac{0}{3} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    3ā‹…0āˆ’12=0āˆ’12=āˆ’12āœ“3\cdot0 - 12 = 0 - 12 = -12 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 12 = -12\ \Rightarrow\ x = 0 \]
\[ 3x - 12 = -12 \]
\[ 3x - 12 + 12 = -12 + 12 \ \Rightarrow\ 3x = 0 \]
\[ \frac{3x}{3} = \frac{0}{3} \ \Rightarrow\ x = 0 \]
\[ 3\cdot0 - 12 = 0 - 12 = -12 \checkmark \]

Trying values of x in 3x āˆ’ 12 = āˆ’12

x3x āˆ’ 12Equals -12?
-2-18no
-1-15no
0-12yes
1-9no
2-6no

Questions

What is x in 3x āˆ’ 12 = āˆ’12?

The solution of 3x āˆ’ 12 = āˆ’12 is x = 0.

How do you solve 3x āˆ’ 12 = āˆ’12?

Add 12 to both sides to get 3x = 0, then divide both sides by 3 to get x = 0.

How do I check the answer?

Replace x by 0: 3(0) āˆ’ 12 = -12, which is -12.

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    Solve 3x āˆ’ 12 = āˆ’12: x = 0 (steps and check) | WordGPT