Solve 3x + 12 = 12
The solution of 3x + 12 = 12 is x = 0.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 0 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 12 = 12\ \Rightarrow\ x = 0 \]
\[ 3x + 12 = 12 \]
\[ 3x + 12 - 12 = 12 - 12 \ \Rightarrow\ 3x = 0 \]
\[ \frac{3x}{3} = \frac{0}{3} \ \Rightarrow\ x = 0 \]
\[ 3\cdot0 + 12 = 0 + 12 = 12 \checkmark \]Trying values of x in 3x + 12 = 12
| x | 3x + 12 | Equals 12? |
|---|---|---|
| -2 | 6 | no |
| -1 | 9 | no |
| 0 | 12 | yes |
| 1 | 15 | no |
| 2 | 18 | no |
Questions
What is x in 3x + 12 = 12?
The solution of 3x + 12 = 12 is x = 0.
How do you solve 3x + 12 = 12?
Subtract 12 from both sides to get 3x = 0, then divide both sides by 3 to get x = 0.
How do I check the answer?
Replace x by 0: 3(0) + 12 = 12, which is 12.