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Solve 4x āˆ’ 12 = āˆ’12

The solution of 4x āˆ’ 12 = āˆ’12 is x = 0.

The lines y = 4x āˆ’ 12 and y = -12 meet at x = 0-6-4-2246-40-30-20-1010x = 0y = 4x āˆ’ 12y = -12
The lines y = 4x āˆ’ 12 and y = -12 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’12=āˆ’124x - 12 = -12
  2. 2

    Add 12 to both sides:

    4xāˆ’12+12=āˆ’12+12 ⇒ 4x=04x - 12 + 12 = -12 + 12 \ \Rightarrow\ 4x = 0
  3. 3

    Divide both sides by 4:

    4x4=04 ⇒ x=0\frac{4x}{4} = \frac{0}{4} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    4ā‹…0āˆ’12=0āˆ’12=āˆ’12āœ“4\cdot0 - 12 = 0 - 12 = -12 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 12 = -12\ \Rightarrow\ x = 0 \]
\[ 4x - 12 = -12 \]
\[ 4x - 12 + 12 = -12 + 12 \ \Rightarrow\ 4x = 0 \]
\[ \frac{4x}{4} = \frac{0}{4} \ \Rightarrow\ x = 0 \]
\[ 4\cdot0 - 12 = 0 - 12 = -12 \checkmark \]

Trying values of x in 4x āˆ’ 12 = āˆ’12

x4x āˆ’ 12Equals -12?
-2-20no
-1-16no
0-12yes
1-8no
2-4no

Questions

What is x in 4x āˆ’ 12 = āˆ’12?

The solution of 4x āˆ’ 12 = āˆ’12 is x = 0.

How do you solve 4x āˆ’ 12 = āˆ’12?

Add 12 to both sides to get 4x = 0, then divide both sides by 4 to get x = 0.

How do I check the answer?

Replace x by 0: 4(0) āˆ’ 12 = -12, which is -12.

Similar equations

    Solve 4x āˆ’ 12 = āˆ’12: x = 0 (steps and check) | WordGPT