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Solve 2x + 1 = āˆ’13

The solution of 2x + 1 = āˆ’13 is x = -7.

The lines y = 2x + 1 and y = -13 meet at x = -7-12-10-8-6-4-2-25-20-15-10-5x = -7y = 2x + 1y = -13
The lines y = 2x + 1 and y = -13 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+1=āˆ’132x + 1 = -13
  2. 2

    Subtract 1 from both sides:

    2x+1āˆ’1=āˆ’13āˆ’1 ⇒ 2x=āˆ’142x + 1 - 1 = -13 - 1 \ \Rightarrow\ 2x = -14
  3. 3

    Divide both sides by 2:

    2x2=āˆ’142 ⇒ x=āˆ’7\frac{2x}{2} = \frac{-14}{2} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    2ā‹…(āˆ’7)+1=āˆ’14+1=āˆ’13āœ“2\cdot(-7) + 1 = -14 + 1 = -13 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 1 = -13\ \Rightarrow\ x = -7 \]
\[ 2x + 1 = -13 \]
\[ 2x + 1 - 1 = -13 - 1 \ \Rightarrow\ 2x = -14 \]
\[ \frac{2x}{2} = \frac{-14}{2} \ \Rightarrow\ x = -7 \]
\[ 2\cdot(-7) + 1 = -14 + 1 = -13 \checkmark \]

Trying values of x in 2x + 1 = āˆ’13

x2x + 1Equals -13?
-9-17no
-8-15no
-7-13yes
-6-11no
-5-9no

Questions

What is x in 2x + 1 = āˆ’13?

The solution of 2x + 1 = āˆ’13 is x = -7.

How do you solve 2x + 1 = āˆ’13?

Subtract 1 from both sides to get 2x = -14, then divide both sides by 2 to get x = -7.

How do I check the answer?

Replace x by -7: 2(-7) + 1 = -13, which is -13.

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    Solve 2x + 1 = āˆ’13: x = -7 (steps and check) | WordGPT