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Solve 2x + 1 = āˆ’11

The solution of 2x + 1 = āˆ’11 is x = -6.

The lines y = 2x + 1 and y = -11 meet at x = -6-12-10-8-6-4-2-25-20-15-10-5x = -6y = 2x + 1y = -11
The lines y = 2x + 1 and y = -11 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+1=āˆ’112x + 1 = -11
  2. 2

    Subtract 1 from both sides:

    2x+1āˆ’1=āˆ’11āˆ’1 ⇒ 2x=āˆ’122x + 1 - 1 = -11 - 1 \ \Rightarrow\ 2x = -12
  3. 3

    Divide both sides by 2:

    2x2=āˆ’122 ⇒ x=āˆ’6\frac{2x}{2} = \frac{-12}{2} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    2ā‹…(āˆ’6)+1=āˆ’12+1=āˆ’11āœ“2\cdot(-6) + 1 = -12 + 1 = -11 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 1 = -11\ \Rightarrow\ x = -6 \]
\[ 2x + 1 = -11 \]
\[ 2x + 1 - 1 = -11 - 1 \ \Rightarrow\ 2x = -12 \]
\[ \frac{2x}{2} = \frac{-12}{2} \ \Rightarrow\ x = -6 \]
\[ 2\cdot(-6) + 1 = -12 + 1 = -11 \checkmark \]

Trying values of x in 2x + 1 = āˆ’11

x2x + 1Equals -11?
-8-15no
-7-13no
-6-11yes
-5-9no
-4-7no

Questions

What is x in 2x + 1 = āˆ’11?

The solution of 2x + 1 = āˆ’11 is x = -6.

How do you solve 2x + 1 = āˆ’11?

Subtract 1 from both sides to get 2x = -12, then divide both sides by 2 to get x = -6.

How do I check the answer?

Replace x by -6: 2(-6) + 1 = -11, which is -11.

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    Solve 2x + 1 = āˆ’11: x = -6 (steps and check) | WordGPT