Solve 12x + 5 = 53
The solution of 12x + 5 = 53 is x = 4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 4 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 5 = 53\ \Rightarrow\ x = 4 \]
\[ 12x + 5 = 53 \]
\[ 12x + 5 - 5 = 53 - 5 \ \Rightarrow\ 12x = 48 \]
\[ \frac{12x}{12} = \frac{48}{12} \ \Rightarrow\ x = 4 \]
\[ 12\cdot4 + 5 = 48 + 5 = 53 \checkmark \]Trying values of x in 12x + 5 = 53
| x | 12x + 5 | Equals 53? |
|---|---|---|
| 2 | 29 | no |
| 3 | 41 | no |
| 4 | 53 | yes |
| 5 | 65 | no |
| 6 | 77 | no |
Questions
What is x in 12x + 5 = 53?
The solution of 12x + 5 = 53 is x = 4.
How do you solve 12x + 5 = 53?
Subtract 5 from both sides to get 12x = 48, then divide both sides by 12 to get x = 4.
How do I check the answer?
Replace x by 4: 12(4) + 5 = 53, which is 53.