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Solve 12x āˆ’ 5 = 43

The solution of 12x āˆ’ 5 = 43 is x = 4.

The lines y = 12x āˆ’ 5 and y = 43 meet at x = 4-2246810-40-2020406080100120x = 4y = 12x āˆ’ 5y = 43
The lines y = 12x āˆ’ 5 and y = 43 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’5=4312x - 5 = 43
  2. 2

    Add 5 to both sides:

    12xāˆ’5+5=43+5 ⇒ 12x=4812x - 5 + 5 = 43 + 5 \ \Rightarrow\ 12x = 48
  3. 3

    Divide both sides by 12:

    12x12=4812 ⇒ x=4\frac{12x}{12} = \frac{48}{12} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    12ā‹…4āˆ’5=48āˆ’5=43āœ“12\cdot4 - 5 = 48 - 5 = 43 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 5 = 43\ \Rightarrow\ x = 4 \]
\[ 12x - 5 = 43 \]
\[ 12x - 5 + 5 = 43 + 5 \ \Rightarrow\ 12x = 48 \]
\[ \frac{12x}{12} = \frac{48}{12} \ \Rightarrow\ x = 4 \]
\[ 12\cdot4 - 5 = 48 - 5 = 43 \checkmark \]

Trying values of x in 12x āˆ’ 5 = 43

x12x āˆ’ 5Equals 43?
219no
331no
443yes
555no
667no

Questions

What is x in 12x āˆ’ 5 = 43?

The solution of 12x āˆ’ 5 = 43 is x = 4.

How do you solve 12x āˆ’ 5 = 43?

Add 5 to both sides to get 12x = 48, then divide both sides by 12 to get x = 4.

How do I check the answer?

Replace x by 4: 12(4) āˆ’ 5 = 43, which is 43.

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    Solve 12x āˆ’ 5 = 43: x = 4 (steps and check) | WordGPT