Solve 12x + 5 = 41
The solution of 12x + 5 = 41 is x = 3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 3 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 5 = 41\ \Rightarrow\ x = 3 \]
\[ 12x + 5 = 41 \]
\[ 12x + 5 - 5 = 41 - 5 \ \Rightarrow\ 12x = 36 \]
\[ \frac{12x}{12} = \frac{36}{12} \ \Rightarrow\ x = 3 \]
\[ 12\cdot3 + 5 = 36 + 5 = 41 \checkmark \]Trying values of x in 12x + 5 = 41
| x | 12x + 5 | Equals 41? |
|---|---|---|
| 1 | 17 | no |
| 2 | 29 | no |
| 3 | 41 | yes |
| 4 | 53 | no |
| 5 | 65 | no |
Questions
What is x in 12x + 5 = 41?
The solution of 12x + 5 = 41 is x = 3.
How do you solve 12x + 5 = 41?
Subtract 5 from both sides to get 12x = 36, then divide both sides by 12 to get x = 3.
How do I check the answer?
Replace x by 3: 12(3) + 5 = 41, which is 41.