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Solve 12x + 4 = āˆ’32

The solution of 12x + 4 = āˆ’32 is x = -3.

The lines y = 12x + 4 and y = -32 meet at x = -3-8-6-4-22-100-80-60-40-202040x = -3y = 12x + 4y = -32
The lines y = 12x + 4 and y = -32 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+4=āˆ’3212x + 4 = -32
  2. 2

    Subtract 4 from both sides:

    12x+4āˆ’4=āˆ’32āˆ’4 ⇒ 12x=āˆ’3612x + 4 - 4 = -32 - 4 \ \Rightarrow\ 12x = -36
  3. 3

    Divide both sides by 12:

    12x12=āˆ’3612 ⇒ x=āˆ’3\frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    12ā‹…(āˆ’3)+4=āˆ’36+4=āˆ’32āœ“12\cdot(-3) + 4 = -36 + 4 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 4 = -32\ \Rightarrow\ x = -3 \]
\[ 12x + 4 = -32 \]
\[ 12x + 4 - 4 = -32 - 4 \ \Rightarrow\ 12x = -36 \]
\[ \frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3 \]
\[ 12\cdot(-3) + 4 = -36 + 4 = -32 \checkmark \]

Trying values of x in 12x + 4 = āˆ’32

x12x + 4Equals -32?
-5-56no
-4-44no
-3-32yes
-2-20no
-1-8no

Questions

What is x in 12x + 4 = āˆ’32?

The solution of 12x + 4 = āˆ’32 is x = -3.

How do you solve 12x + 4 = āˆ’32?

Subtract 4 from both sides to get 12x = -36, then divide both sides by 12 to get x = -3.

How do I check the answer?

Replace x by -3: 12(-3) + 4 = -32, which is -32.

Similar equations

    Solve 12x + 4 = āˆ’32: x = -3 (steps and check) | WordGPT