Solve 12x + 4 = ā32
The solution of 12x + 4 = ā32 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 4 = -32\ \Rightarrow\ x = -3 \]
\[ 12x + 4 = -32 \]
\[ 12x + 4 - 4 = -32 - 4 \ \Rightarrow\ 12x = -36 \]
\[ \frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3 \]
\[ 12\cdot(-3) + 4 = -36 + 4 = -32 \checkmark \]Trying values of x in 12x + 4 = ā32
| x | 12x + 4 | Equals -32? |
|---|---|---|
| -5 | -56 | no |
| -4 | -44 | no |
| -3 | -32 | yes |
| -2 | -20 | no |
| -1 | -8 | no |
Questions
What is x in 12x + 4 = ā32?
The solution of 12x + 4 = ā32 is x = -3.
How do you solve 12x + 4 = ā32?
Subtract 4 from both sides to get 12x = -36, then divide both sides by 12 to get x = -3.
How do I check the answer?
Replace x by -3: 12(-3) + 4 = -32, which is -32.