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Solve 12x āˆ’ 4 = āˆ’40

The solution of 12x āˆ’ 4 = āˆ’40 is x = -3.

The lines y = 12x āˆ’ 4 and y = -40 meet at x = -3-8-6-4-22-120-100-80-60-40-202040x = -3y = 12x āˆ’ 4y = -40
The lines y = 12x āˆ’ 4 and y = -40 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’4=āˆ’4012x - 4 = -40
  2. 2

    Add 4 to both sides:

    12xāˆ’4+4=āˆ’40+4 ⇒ 12x=āˆ’3612x - 4 + 4 = -40 + 4 \ \Rightarrow\ 12x = -36
  3. 3

    Divide both sides by 12:

    12x12=āˆ’3612 ⇒ x=āˆ’3\frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    12ā‹…(āˆ’3)āˆ’4=āˆ’36āˆ’4=āˆ’40āœ“12\cdot(-3) - 4 = -36 - 4 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 4 = -40\ \Rightarrow\ x = -3 \]
\[ 12x - 4 = -40 \]
\[ 12x - 4 + 4 = -40 + 4 \ \Rightarrow\ 12x = -36 \]
\[ \frac{12x}{12} = \frac{-36}{12} \ \Rightarrow\ x = -3 \]
\[ 12\cdot(-3) - 4 = -36 - 4 = -40 \checkmark \]

Trying values of x in 12x āˆ’ 4 = āˆ’40

x12x āˆ’ 4Equals -40?
-5-64no
-4-52no
-3-40yes
-2-28no
-1-16no

Questions

What is x in 12x āˆ’ 4 = āˆ’40?

The solution of 12x āˆ’ 4 = āˆ’40 is x = -3.

How do you solve 12x āˆ’ 4 = āˆ’40?

Add 4 to both sides to get 12x = -36, then divide both sides by 12 to get x = -3.

How do I check the answer?

Replace x by -3: 12(-3) āˆ’ 4 = -40, which is -40.

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    Solve 12x āˆ’ 4 = āˆ’40: x = -3 (steps and check) | WordGPT