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Solve 12x + 4 = āˆ’20

The solution of 12x + 4 = āˆ’20 is x = -2.

The lines y = 12x + 4 and y = -20 meet at x = -2-8-6-4-224-100-80-60-40-20204060x = -2y = 12x + 4y = -20
The lines y = 12x + 4 and y = -20 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+4=āˆ’2012x + 4 = -20
  2. 2

    Subtract 4 from both sides:

    12x+4āˆ’4=āˆ’20āˆ’4 ⇒ 12x=āˆ’2412x + 4 - 4 = -20 - 4 \ \Rightarrow\ 12x = -24
  3. 3

    Divide both sides by 12:

    12x12=āˆ’2412 ⇒ x=āˆ’2\frac{12x}{12} = \frac{-24}{12} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    12ā‹…(āˆ’2)+4=āˆ’24+4=āˆ’20āœ“12\cdot(-2) + 4 = -24 + 4 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 4 = -20\ \Rightarrow\ x = -2 \]
\[ 12x + 4 = -20 \]
\[ 12x + 4 - 4 = -20 - 4 \ \Rightarrow\ 12x = -24 \]
\[ \frac{12x}{12} = \frac{-24}{12} \ \Rightarrow\ x = -2 \]
\[ 12\cdot(-2) + 4 = -24 + 4 = -20 \checkmark \]

Trying values of x in 12x + 4 = āˆ’20

x12x + 4Equals -20?
-4-44no
-3-32no
-2-20yes
-1-8no
04no

Questions

What is x in 12x + 4 = āˆ’20?

The solution of 12x + 4 = āˆ’20 is x = -2.

How do you solve 12x + 4 = āˆ’20?

Subtract 4 from both sides to get 12x = -24, then divide both sides by 12 to get x = -2.

How do I check the answer?

Replace x by -2: 12(-2) + 4 = -20, which is -20.

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    Solve 12x + 4 = āˆ’20: x = -2 (steps and check) | WordGPT