Solve 11x + 2 = 68
The solution of 11x + 2 = 68 is x = 6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 6 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 2 = 68\ \Rightarrow\ x = 6 \]
\[ 11x + 2 = 68 \]
\[ 11x + 2 - 2 = 68 - 2 \ \Rightarrow\ 11x = 66 \]
\[ \frac{11x}{11} = \frac{66}{11} \ \Rightarrow\ x = 6 \]
\[ 11\cdot6 + 2 = 66 + 2 = 68 \checkmark \]Trying values of x in 11x + 2 = 68
| x | 11x + 2 | Equals 68? |
|---|---|---|
| 4 | 46 | no |
| 5 | 57 | no |
| 6 | 68 | yes |
| 7 | 79 | no |
| 8 | 90 | no |
Questions
What is x in 11x + 2 = 68?
The solution of 11x + 2 = 68 is x = 6.
How do you solve 11x + 2 = 68?
Subtract 2 from both sides to get 11x = 66, then divide both sides by 11 to get x = 6.
How do I check the answer?
Replace x by 6: 11(6) + 2 = 68, which is 68.