Solve 11x + 2 = 57
The solution of 11x + 2 = 57 is x = 5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 5 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 2 = 57\ \Rightarrow\ x = 5 \]
\[ 11x + 2 = 57 \]
\[ 11x + 2 - 2 = 57 - 2 \ \Rightarrow\ 11x = 55 \]
\[ \frac{11x}{11} = \frac{55}{11} \ \Rightarrow\ x = 5 \]
\[ 11\cdot5 + 2 = 55 + 2 = 57 \checkmark \]Trying values of x in 11x + 2 = 57
| x | 11x + 2 | Equals 57? |
|---|---|---|
| 3 | 35 | no |
| 4 | 46 | no |
| 5 | 57 | yes |
| 6 | 68 | no |
| 7 | 79 | no |
Questions
What is x in 11x + 2 = 57?
The solution of 11x + 2 = 57 is x = 5.
How do you solve 11x + 2 = 57?
Subtract 2 from both sides to get 11x = 55, then divide both sides by 11 to get x = 5.
How do I check the answer?
Replace x by 5: 11(5) + 2 = 57, which is 57.