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Solve 11x āˆ’ 2 = 64

The solution of 11x āˆ’ 2 = 64 is x = 6.

The lines y = 11x āˆ’ 2 and y = 64 meet at x = 62468101220406080100120140x = 6y = 11x āˆ’ 2y = 64
The lines y = 11x āˆ’ 2 and y = 64 meet at x = 6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’2=6411x - 2 = 64
  2. 2

    Add 2 to both sides:

    11xāˆ’2+2=64+2 ⇒ 11x=6611x - 2 + 2 = 64 + 2 \ \Rightarrow\ 11x = 66
  3. 3

    Divide both sides by 11:

    11x11=6611 ⇒ x=6\frac{11x}{11} = \frac{66}{11} \ \Rightarrow\ x = 6
  4. 4

    Check: put x = 6 back into the equation.

    11ā‹…6āˆ’2=66āˆ’2=64āœ“11\cdot6 - 2 = 66 - 2 = 64 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 2 = 64\ \Rightarrow\ x = 6 \]
\[ 11x - 2 = 64 \]
\[ 11x - 2 + 2 = 64 + 2 \ \Rightarrow\ 11x = 66 \]
\[ \frac{11x}{11} = \frac{66}{11} \ \Rightarrow\ x = 6 \]
\[ 11\cdot6 - 2 = 66 - 2 = 64 \checkmark \]

Trying values of x in 11x āˆ’ 2 = 64

x11x āˆ’ 2Equals 64?
442no
553no
664yes
775no
886no

Questions

What is x in 11x āˆ’ 2 = 64?

The solution of 11x āˆ’ 2 = 64 is x = 6.

How do you solve 11x āˆ’ 2 = 64?

Add 2 to both sides to get 11x = 66, then divide both sides by 11 to get x = 6.

How do I check the answer?

Replace x by 6: 11(6) āˆ’ 2 = 64, which is 64.

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