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Solve 11x āˆ’ 5 = āˆ’82

The solution of 11x āˆ’ 5 = āˆ’82 is x = -7.

The lines y = 11x āˆ’ 5 and y = -82 meet at x = -7-12-10-8-6-4-2-160-140-120-100-80-60-40-20x = -7y = 11x āˆ’ 5y = -82
The lines y = 11x āˆ’ 5 and y = -82 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’5=āˆ’8211x - 5 = -82
  2. 2

    Add 5 to both sides:

    11xāˆ’5+5=āˆ’82+5 ⇒ 11x=āˆ’7711x - 5 + 5 = -82 + 5 \ \Rightarrow\ 11x = -77
  3. 3

    Divide both sides by 11:

    11x11=āˆ’7711 ⇒ x=āˆ’7\frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    11ā‹…(āˆ’7)āˆ’5=āˆ’77āˆ’5=āˆ’82āœ“11\cdot(-7) - 5 = -77 - 5 = -82 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 5 = -82\ \Rightarrow\ x = -7 \]
\[ 11x - 5 = -82 \]
\[ 11x - 5 + 5 = -82 + 5 \ \Rightarrow\ 11x = -77 \]
\[ \frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7 \]
\[ 11\cdot(-7) - 5 = -77 - 5 = -82 \checkmark \]

Trying values of x in 11x āˆ’ 5 = āˆ’82

x11x āˆ’ 5Equals -82?
-9-104no
-8-93no
-7-82yes
-6-71no
-5-60no

Questions

What is x in 11x āˆ’ 5 = āˆ’82?

The solution of 11x āˆ’ 5 = āˆ’82 is x = -7.

How do you solve 11x āˆ’ 5 = āˆ’82?

Add 5 to both sides to get 11x = -77, then divide both sides by 11 to get x = -7.

How do I check the answer?

Replace x by -7: 11(-7) āˆ’ 5 = -82, which is -82.

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    Solve 11x āˆ’ 5 = āˆ’82: x = -7 (steps and check) | WordGPT