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Solve 11x āˆ’ 5 = āˆ’71

The solution of 11x āˆ’ 5 = āˆ’71 is x = -6.

The lines y = 11x āˆ’ 5 and y = -71 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 11x āˆ’ 5y = -71
The lines y = 11x āˆ’ 5 and y = -71 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’5=āˆ’7111x - 5 = -71
  2. 2

    Add 5 to both sides:

    11xāˆ’5+5=āˆ’71+5 ⇒ 11x=āˆ’6611x - 5 + 5 = -71 + 5 \ \Rightarrow\ 11x = -66
  3. 3

    Divide both sides by 11:

    11x11=āˆ’6611 ⇒ x=āˆ’6\frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    11ā‹…(āˆ’6)āˆ’5=āˆ’66āˆ’5=āˆ’71āœ“11\cdot(-6) - 5 = -66 - 5 = -71 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 5 = -71\ \Rightarrow\ x = -6 \]
\[ 11x - 5 = -71 \]
\[ 11x - 5 + 5 = -71 + 5 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) - 5 = -66 - 5 = -71 \checkmark \]

Trying values of x in 11x āˆ’ 5 = āˆ’71

x11x āˆ’ 5Equals -71?
-8-93no
-7-82no
-6-71yes
-5-60no
-4-49no

Questions

What is x in 11x āˆ’ 5 = āˆ’71?

The solution of 11x āˆ’ 5 = āˆ’71 is x = -6.

How do you solve 11x āˆ’ 5 = āˆ’71?

Add 5 to both sides to get 11x = -66, then divide both sides by 11 to get x = -6.

How do I check the answer?

Replace x by -6: 11(-6) āˆ’ 5 = -71, which is -71.

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    Solve 11x āˆ’ 5 = āˆ’71: x = -6 (steps and check) | WordGPT