Solve 11x + 5 = ā72
The solution of 11x + 5 = ā72 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 5 = -72\ \Rightarrow\ x = -7 \]
\[ 11x + 5 = -72 \]
\[ 11x + 5 - 5 = -72 - 5 \ \Rightarrow\ 11x = -77 \]
\[ \frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7 \]
\[ 11\cdot(-7) + 5 = -77 + 5 = -72 \checkmark \]Trying values of x in 11x + 5 = ā72
| x | 11x + 5 | Equals -72? |
|---|---|---|
| -9 | -94 | no |
| -8 | -83 | no |
| -7 | -72 | yes |
| -6 | -61 | no |
| -5 | -50 | no |
Questions
What is x in 11x + 5 = ā72?
The solution of 11x + 5 = ā72 is x = -7.
How do you solve 11x + 5 = ā72?
Subtract 5 from both sides to get 11x = -77, then divide both sides by 11 to get x = -7.
How do I check the answer?
Replace x by -7: 11(-7) + 5 = -72, which is -72.