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Solve 11x āˆ’ 15 = āˆ’4

The solution of 11x āˆ’ 15 = āˆ’4 is x = 1.

The lines y = 11x āˆ’ 15 and y = -4 meet at x = 1-4-2246-80-60-40-20204060x = 1y = 11x āˆ’ 15y = -4
The lines y = 11x āˆ’ 15 and y = -4 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’15=āˆ’411x - 15 = -4
  2. 2

    Add 15 to both sides:

    11xāˆ’15+15=āˆ’4+15 ⇒ 11x=1111x - 15 + 15 = -4 + 15 \ \Rightarrow\ 11x = 11
  3. 3

    Divide both sides by 11:

    11x11=1111 ⇒ x=1\frac{11x}{11} = \frac{11}{11} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    11ā‹…1āˆ’15=11āˆ’15=āˆ’4āœ“11\cdot1 - 15 = 11 - 15 = -4 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 15 = -4\ \Rightarrow\ x = 1 \]
\[ 11x - 15 = -4 \]
\[ 11x - 15 + 15 = -4 + 15 \ \Rightarrow\ 11x = 11 \]
\[ \frac{11x}{11} = \frac{11}{11} \ \Rightarrow\ x = 1 \]
\[ 11\cdot1 - 15 = 11 - 15 = -4 \checkmark \]

Trying values of x in 11x āˆ’ 15 = āˆ’4

x11x āˆ’ 15Equals -4?
-1-26no
0-15no
1-4yes
27no
318no

Questions

What is x in 11x āˆ’ 15 = āˆ’4?

The solution of 11x āˆ’ 15 = āˆ’4 is x = 1.

How do you solve 11x āˆ’ 15 = āˆ’4?

Add 15 to both sides to get 11x = 11, then divide both sides by 11 to get x = 1.

How do I check the answer?

Replace x by 1: 11(1) āˆ’ 15 = -4, which is -4.

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    Solve 11x āˆ’ 15 = āˆ’4: x = 1 (steps and check) | WordGPT