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Solve 12x āˆ’ 15 = āˆ’3

The solution of 12x āˆ’ 15 = āˆ’3 is x = 1.

The lines y = 12x āˆ’ 15 and y = -3 meet at x = 1-4-2246-80-60-40-2020406080x = 1y = 12x āˆ’ 15y = -3
The lines y = 12x āˆ’ 15 and y = -3 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’15=āˆ’312x - 15 = -3
  2. 2

    Add 15 to both sides:

    12xāˆ’15+15=āˆ’3+15 ⇒ 12x=1212x - 15 + 15 = -3 + 15 \ \Rightarrow\ 12x = 12
  3. 3

    Divide both sides by 12:

    12x12=1212 ⇒ x=1\frac{12x}{12} = \frac{12}{12} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    12ā‹…1āˆ’15=12āˆ’15=āˆ’3āœ“12\cdot1 - 15 = 12 - 15 = -3 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 15 = -3\ \Rightarrow\ x = 1 \]
\[ 12x - 15 = -3 \]
\[ 12x - 15 + 15 = -3 + 15 \ \Rightarrow\ 12x = 12 \]
\[ \frac{12x}{12} = \frac{12}{12} \ \Rightarrow\ x = 1 \]
\[ 12\cdot1 - 15 = 12 - 15 = -3 \checkmark \]

Trying values of x in 12x āˆ’ 15 = āˆ’3

x12x āˆ’ 15Equals -3?
-1-27no
0-15no
1-3yes
29no
321no

Questions

What is x in 12x āˆ’ 15 = āˆ’3?

The solution of 12x āˆ’ 15 = āˆ’3 is x = 1.

How do you solve 12x āˆ’ 15 = āˆ’3?

Add 15 to both sides to get 12x = 12, then divide both sides by 12 to get x = 1.

How do I check the answer?

Replace x by 1: 12(1) āˆ’ 15 = -3, which is -3.

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    Solve 12x āˆ’ 15 = āˆ’3: x = 1 (steps and check) | WordGPT