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Solve 11x āˆ’ 15 = āˆ’15

The solution of 11x āˆ’ 15 = āˆ’15 is x = 0.

The lines y = 11x āˆ’ 15 and y = -15 meet at x = 0-6-4-2246-80-60-40-20204060x = 0y = 11x āˆ’ 15y = -15
The lines y = 11x āˆ’ 15 and y = -15 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’15=āˆ’1511x - 15 = -15
  2. 2

    Add 15 to both sides:

    11xāˆ’15+15=āˆ’15+15 ⇒ 11x=011x - 15 + 15 = -15 + 15 \ \Rightarrow\ 11x = 0
  3. 3

    Divide both sides by 11:

    11x11=011 ⇒ x=0\frac{11x}{11} = \frac{0}{11} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    11ā‹…0āˆ’15=0āˆ’15=āˆ’15āœ“11\cdot0 - 15 = 0 - 15 = -15 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 15 = -15\ \Rightarrow\ x = 0 \]
\[ 11x - 15 = -15 \]
\[ 11x - 15 + 15 = -15 + 15 \ \Rightarrow\ 11x = 0 \]
\[ \frac{11x}{11} = \frac{0}{11} \ \Rightarrow\ x = 0 \]
\[ 11\cdot0 - 15 = 0 - 15 = -15 \checkmark \]

Trying values of x in 11x āˆ’ 15 = āˆ’15

x11x āˆ’ 15Equals -15?
-2-37no
-1-26no
0-15yes
1-4no
27no

Questions

What is x in 11x āˆ’ 15 = āˆ’15?

The solution of 11x āˆ’ 15 = āˆ’15 is x = 0.

How do you solve 11x āˆ’ 15 = āˆ’15?

Add 15 to both sides to get 11x = 0, then divide both sides by 11 to get x = 0.

How do I check the answer?

Replace x by 0: 11(0) āˆ’ 15 = -15, which is -15.

Similar equations

    Solve 11x āˆ’ 15 = āˆ’15: x = 0 (steps and check) | WordGPT