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Solve 10x + 5 = āˆ’25

The solution of 10x + 5 = āˆ’25 is x = -3.

The lines y = 10x + 5 and y = -25 meet at x = -3-8-6-4-22-80-60-40-202040x = -3y = 10x + 5y = -25
The lines y = 10x + 5 and y = -25 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+5=āˆ’2510x + 5 = -25
  2. 2

    Subtract 5 from both sides:

    10x+5āˆ’5=āˆ’25āˆ’5 ⇒ 10x=āˆ’3010x + 5 - 5 = -25 - 5 \ \Rightarrow\ 10x = -30
  3. 3

    Divide both sides by 10:

    10x10=āˆ’3010 ⇒ x=āˆ’3\frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    10ā‹…(āˆ’3)+5=āˆ’30+5=āˆ’25āœ“10\cdot(-3) + 5 = -30 + 5 = -25 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 5 = -25\ \Rightarrow\ x = -3 \]
\[ 10x + 5 = -25 \]
\[ 10x + 5 - 5 = -25 - 5 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) + 5 = -30 + 5 = -25 \checkmark \]

Trying values of x in 10x + 5 = āˆ’25

x10x + 5Equals -25?
-5-45no
-4-35no
-3-25yes
-2-15no
-1-5no

Questions

What is x in 10x + 5 = āˆ’25?

The solution of 10x + 5 = āˆ’25 is x = -3.

How do you solve 10x + 5 = āˆ’25?

Subtract 5 from both sides to get 10x = -30, then divide both sides by 10 to get x = -3.

How do I check the answer?

Replace x by -3: 10(-3) + 5 = -25, which is -25.

Similar equations

    Solve 10x + 5 = āˆ’25: x = -3 (steps and check) | WordGPT