Solve 10x + 5 = ā15
The solution of 10x + 5 = ā15 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 5 = -15\ \Rightarrow\ x = -2 \]
\[ 10x + 5 = -15 \]
\[ 10x + 5 - 5 = -15 - 5 \ \Rightarrow\ 10x = -20 \]
\[ \frac{10x}{10} = \frac{-20}{10} \ \Rightarrow\ x = -2 \]
\[ 10\cdot(-2) + 5 = -20 + 5 = -15 \checkmark \]Trying values of x in 10x + 5 = ā15
| x | 10x + 5 | Equals -15? |
|---|---|---|
| -4 | -35 | no |
| -3 | -25 | no |
| -2 | -15 | yes |
| -1 | -5 | no |
| 0 | 5 | no |
Questions
What is x in 10x + 5 = ā15?
The solution of 10x + 5 = ā15 is x = -2.
How do you solve 10x + 5 = ā15?
Subtract 5 from both sides to get 10x = -20, then divide both sides by 10 to get x = -2.
How do I check the answer?
Replace x by -2: 10(-2) + 5 = -15, which is -15.