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Solve 10x + 5 = āˆ’5

The solution of 10x + 5 = āˆ’5 is x = -1.

The lines y = 10x + 5 and y = -5 meet at x = -1-6-4-224-60-40-20204060x = -1y = 10x + 5y = -5
The lines y = 10x + 5 and y = -5 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+5=āˆ’510x + 5 = -5
  2. 2

    Subtract 5 from both sides:

    10x+5āˆ’5=āˆ’5āˆ’5 ⇒ 10x=āˆ’1010x + 5 - 5 = -5 - 5 \ \Rightarrow\ 10x = -10
  3. 3

    Divide both sides by 10:

    10x10=āˆ’1010 ⇒ x=āˆ’1\frac{10x}{10} = \frac{-10}{10} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    10ā‹…(āˆ’1)+5=āˆ’10+5=āˆ’5āœ“10\cdot(-1) + 5 = -10 + 5 = -5 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 5 = -5\ \Rightarrow\ x = -1 \]
\[ 10x + 5 = -5 \]
\[ 10x + 5 - 5 = -5 - 5 \ \Rightarrow\ 10x = -10 \]
\[ \frac{10x}{10} = \frac{-10}{10} \ \Rightarrow\ x = -1 \]
\[ 10\cdot(-1) + 5 = -10 + 5 = -5 \checkmark \]

Trying values of x in 10x + 5 = āˆ’5

x10x + 5Equals -5?
-3-25no
-2-15no
-1-5yes
05no
115no

Questions

What is x in 10x + 5 = āˆ’5?

The solution of 10x + 5 = āˆ’5 is x = -1.

How do you solve 10x + 5 = āˆ’5?

Subtract 5 from both sides to get 10x = -10, then divide both sides by 10 to get x = -1.

How do I check the answer?

Replace x by -1: 10(-1) + 5 = -5, which is -5.

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    Solve 10x + 5 = āˆ’5: x = -1 (steps and check) | WordGPT