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Solve 10x + 10 = āˆ’20

The solution of 10x + 10 = āˆ’20 is x = -3.

The lines y = 10x + 10 and y = -20 meet at x = -3-8-6-4-22-80-60-40-202040x = -3y = 10x + 10y = -20
The lines y = 10x + 10 and y = -20 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+10=āˆ’2010x + 10 = -20
  2. 2

    Subtract 10 from both sides:

    10x+10āˆ’10=āˆ’20āˆ’10 ⇒ 10x=āˆ’3010x + 10 - 10 = -20 - 10 \ \Rightarrow\ 10x = -30
  3. 3

    Divide both sides by 10:

    10x10=āˆ’3010 ⇒ x=āˆ’3\frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    10ā‹…(āˆ’3)+10=āˆ’30+10=āˆ’20āœ“10\cdot(-3) + 10 = -30 + 10 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 10 = -20\ \Rightarrow\ x = -3 \]
\[ 10x + 10 = -20 \]
\[ 10x + 10 - 10 = -20 - 10 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) + 10 = -30 + 10 = -20 \checkmark \]

Trying values of x in 10x + 10 = āˆ’20

x10x + 10Equals -20?
-5-40no
-4-30no
-3-20yes
-2-10no
-10no

Questions

What is x in 10x + 10 = āˆ’20?

The solution of 10x + 10 = āˆ’20 is x = -3.

How do you solve 10x + 10 = āˆ’20?

Subtract 10 from both sides to get 10x = -30, then divide both sides by 10 to get x = -3.

How do I check the answer?

Replace x by -3: 10(-3) + 10 = -20, which is -20.

Similar equations

    Solve 10x + 10 = āˆ’20: x = -3 (steps and check) | WordGPT