Solve 10x ā 10 = ā40
The solution of 10x ā 10 = ā40 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 10 to both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 10x - 10 = -40\ \Rightarrow\ x = -3 \]
\[ 10x - 10 = -40 \]
\[ 10x - 10 + 10 = -40 + 10 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) - 10 = -30 - 10 = -40 \checkmark \]Trying values of x in 10x ā 10 = ā40
| x | 10x ā 10 | Equals -40? |
|---|---|---|
| -5 | -60 | no |
| -4 | -50 | no |
| -3 | -40 | yes |
| -2 | -30 | no |
| -1 | -20 | no |
Questions
What is x in 10x ā 10 = ā40?
The solution of 10x ā 10 = ā40 is x = -3.
How do you solve 10x ā 10 = ā40?
Add 10 to both sides to get 10x = -30, then divide both sides by 10 to get x = -3.
How do I check the answer?
Replace x by -3: 10(-3) ā 10 = -40, which is -40.