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Solve 10x āˆ’ 10 = āˆ’40

The solution of 10x āˆ’ 10 = āˆ’40 is x = -3.

The lines y = 10x āˆ’ 10 and y = -40 meet at x = -3-8-6-4-22-100-80-60-40-2020x = -3y = 10x āˆ’ 10y = -40
The lines y = 10x āˆ’ 10 and y = -40 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’10=āˆ’4010x - 10 = -40
  2. 2

    Add 10 to both sides:

    10xāˆ’10+10=āˆ’40+10 ⇒ 10x=āˆ’3010x - 10 + 10 = -40 + 10 \ \Rightarrow\ 10x = -30
  3. 3

    Divide both sides by 10:

    10x10=āˆ’3010 ⇒ x=āˆ’3\frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    10ā‹…(āˆ’3)āˆ’10=āˆ’30āˆ’10=āˆ’40āœ“10\cdot(-3) - 10 = -30 - 10 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 10 = -40\ \Rightarrow\ x = -3 \]
\[ 10x - 10 = -40 \]
\[ 10x - 10 + 10 = -40 + 10 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) - 10 = -30 - 10 = -40 \checkmark \]

Trying values of x in 10x āˆ’ 10 = āˆ’40

x10x āˆ’ 10Equals -40?
-5-60no
-4-50no
-3-40yes
-2-30no
-1-20no

Questions

What is x in 10x āˆ’ 10 = āˆ’40?

The solution of 10x āˆ’ 10 = āˆ’40 is x = -3.

How do you solve 10x āˆ’ 10 = āˆ’40?

Add 10 to both sides to get 10x = -30, then divide both sides by 10 to get x = -3.

How do I check the answer?

Replace x by -3: 10(-3) āˆ’ 10 = -40, which is -40.

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    Solve 10x āˆ’ 10 = āˆ’40: x = -3 (steps and check) | WordGPT