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Solve 10x + 10 = āˆ’10

The solution of 10x + 10 = āˆ’10 is x = -2.

The lines y = 10x + 10 and y = -10 meet at x = -2-8-6-4-224-80-60-40-20204060x = -2y = 10x + 10y = -10
The lines y = 10x + 10 and y = -10 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+10=āˆ’1010x + 10 = -10
  2. 2

    Subtract 10 from both sides:

    10x+10āˆ’10=āˆ’10āˆ’10 ⇒ 10x=āˆ’2010x + 10 - 10 = -10 - 10 \ \Rightarrow\ 10x = -20
  3. 3

    Divide both sides by 10:

    10x10=āˆ’2010 ⇒ x=āˆ’2\frac{10x}{10} = \frac{-20}{10} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    10ā‹…(āˆ’2)+10=āˆ’20+10=āˆ’10āœ“10\cdot(-2) + 10 = -20 + 10 = -10 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 10 = -10\ \Rightarrow\ x = -2 \]
\[ 10x + 10 = -10 \]
\[ 10x + 10 - 10 = -10 - 10 \ \Rightarrow\ 10x = -20 \]
\[ \frac{10x}{10} = \frac{-20}{10} \ \Rightarrow\ x = -2 \]
\[ 10\cdot(-2) + 10 = -20 + 10 = -10 \checkmark \]

Trying values of x in 10x + 10 = āˆ’10

x10x + 10Equals -10?
-4-30no
-3-20no
-2-10yes
-10no
010no

Questions

What is x in 10x + 10 = āˆ’10?

The solution of 10x + 10 = āˆ’10 is x = -2.

How do you solve 10x + 10 = āˆ’10?

Subtract 10 from both sides to get 10x = -20, then divide both sides by 10 to get x = -2.

How do I check the answer?

Replace x by -2: 10(-2) + 10 = -10, which is -10.

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    Solve 10x + 10 = āˆ’10: x = -2 (steps and check) | WordGPT