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Solve -3x² - 7 = 0

-3x² - 7 = 0 has no real solutions. The two complex solutions are x = (√21 i)/3 and x = (-√21 i)/3.

x² +x += 0
−3x2−7=0⇒x=21 i3, −21 i3 (complex)-3x^2 - 7 = 0 \Rightarrow x = \frac{\sqrt{21}\, i}{3},\ \frac{-\sqrt{21}\, i}{3}\ \text{(complex)}
Discriminant D = -84

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = -3x² - 7-4-3-2-11234-50-40-30-20-10vertexy = -3x² - 7
Graph of y = -3x² - 7. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0, -7).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -3, b = 0, c = -7.

    −3x2−7=0-3x^2 - 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=02−4⋅(−3)⋅(−7)=0−84=−84D = 0^2 - 4\cdot(-3)\cdot(-7) = 0 - 84 = -84
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=0±−84−6x = \frac{-b \pm \sqrt{D}}{2a} = \frac{0 \pm \sqrt{-84}}{-6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=21 i3orx=−21 i3x = \frac{\sqrt{21}\, i}{3}\quad\text{or}\quad x = \frac{-\sqrt{21}\, i}{3}
LaTeX source of the formulas on this page
\[ -3x^2 - 7 = 0\ \Rightarrow\ x = \frac{\sqrt{21}\, i}{3},\ \frac{-\sqrt{21}\, i}{3} \]
\[ -3x^2 - 7 = 0 \]
\[ D = 0^2 - 4\cdot(-3)\cdot(-7) = 0 - 84 = -84 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{0 \pm \sqrt{-84}}{-6} \]
\[ x = \frac{\sqrt{21}\, i}{3}\quad\text{or}\quad x = \frac{-\sqrt{21}\, i}{3} \]

The parabola y = -3x² - 7

xy
-3-34
-2-19
-1-10
0-7
1-10
2-19
3-34

Questions

What are the solutions of -3x² - 7 = 0?

-3x² - 7 = 0 has no real solutions. The two complex solutions are x = (√21 i)/3 and x = (-√21 i)/3.

Does -3x² - 7 = 0 factor?

Not over the integers, because the discriminant -84 is negative. Use the quadratic formula.

What is the vertex of y = -3x² - 7?

(0, -7). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = 0, product = c/a = 7/3.

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