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Solve -x² - 8x + 10 = 0

The solutions of -x² - 8x + 10 = 0 are x = -4 + √26 or x = -4 - √26, that is x ≈ -9.0990195 and x ≈ 1.0990195.

x² +x += 0
−x2−8x+10=0⇒x=−4+26, −4−26-x^2 - 8x + 10 = 0 \Rightarrow x = -4 + \sqrt{26},\ -4 - \sqrt{26}
Discriminant D = 104 · x ≈ -9.09902, 1.09902

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = -x² - 8x + 10-10-8-6-4-22-30-20-10102030x = -9.0990195x = 1.0990195vertexy = -x² - 8x + 10
Graph of y = -x² - 8x + 10. The curve crosses the x-axis at x = -9.0990195 and x = 1.0990195; the vertex is at (-4, 26).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = -1, b = -8, c = 10.

    −x2−8x+10=0-x^2 - 8x + 10 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−8)2−4⋅(−1)⋅10=64+40=104D = (-8)^2 - 4\cdot(-1)\cdot10 = 64 + 40 = 104
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=8±104−2x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{104}}{-2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+26orx=−4−26x = -4 + \sqrt{26}\quad\text{or}\quad x = -4 - \sqrt{26}
  6. 6

    As decimals: x ≈ -9.0990195 and x ≈ 1.0990195.

  7. 7

    Check numerically: for x ≈ -9.0990195 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ -x^2 - 8x + 10 = 0\ \Rightarrow\ x = -4 + \sqrt{26},\ -4 - \sqrt{26} \]
\[ -x^2 - 8x + 10 = 0 \]
\[ D = (-8)^2 - 4\cdot(-1)\cdot10 = 64 + 40 = 104 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{8 \pm \sqrt{104}}{-2} \]
\[ x = -4 + \sqrt{26}\quad\text{or}\quad x = -4 - \sqrt{26} \]

The parabola y = -x² - 8x + 10

xy
-717
-622
-525
-426
-325
-222
-117

Questions

What are the solutions of -x² - 8x + 10 = 0?

The solutions of -x² - 8x + 10 = 0 are x = -4 + √26 or x = -4 - √26, that is x ≈ -9.0990195 and x ≈ 1.0990195.

Does -x² - 8x + 10 = 0 factor?

Not over the integers, because the discriminant 104 is not a perfect square. Use the quadratic formula.

What is the vertex of y = -x² - 8x + 10?

(-4, 26). The parabola opens downwards, so this is the maximum.

What are the sum and product of the roots?

Sum = −b/a = -8, product = c/a = -10.

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    Solve -x² - 8x + 10 = 0: x = -4 + √26 or x = -4 - √26 (steps) | WordGPT