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Solve 5x² + 5x - 5 = 0

The solutions of 5x² + 5x - 5 = 0 are x = (-1 + √5)/2 or x = (-1 - √5)/2, that is x ≈ 0.61803399 and x ≈ -1.618034.

x² +x += 0
5x2+5x−5=0⇒x=−1+52, −1−525x^2 + 5x - 5 = 0 \Rightarrow x = \frac{-1 + \sqrt{5}}{2},\ \frac{-1 - \sqrt{5}}{2}
Discriminant D = 125 · x ≈ 0.618034, -1.61803

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² + 5x - 5-4-3-2-1123-10102030405060x = 0.61803399x = -1.618034vertexy = 5x² + 5x - 5
Graph of y = 5x² + 5x - 5. The curve crosses the x-axis at x = 0.61803399 and x = -1.618034; the vertex is at (-0.5, -6.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 5, c = -5.

    5x2+5x−5=05x^2 + 5x - 5 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=52−4⋅5⋅(−5)=25+100=125D = 5^2 - 4\cdot5\cdot(-5) = 25 + 100 = 125
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−5±12510x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{125}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−1+52orx=−1−52x = \frac{-1 + \sqrt{5}}{2}\quad\text{or}\quad x = \frac{-1 - \sqrt{5}}{2}
  6. 6

    As decimals: x ≈ 0.61803399 and x ≈ -1.618034.

  7. 7

    Check numerically: for x ≈ 0.61803399 the left side is 8.8817842e-16 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 + 5x - 5 = 0\ \Rightarrow\ x = \frac{-1 + \sqrt{5}}{2},\ \frac{-1 - \sqrt{5}}{2} \]
\[ 5x^2 + 5x - 5 = 0 \]
\[ D = 5^2 - 4\cdot5\cdot(-5) = 25 + 100 = 125 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{125}}{10} \]
\[ x = \frac{-1 + \sqrt{5}}{2}\quad\text{or}\quad x = \frac{-1 - \sqrt{5}}{2} \]

The parabola y = 5x² + 5x - 5

xy
-3.538.75
-2.513.75
-1.5-1.25
-0.5-6.25
0.5-1.25
1.513.75
2.538.75

Questions

What are the solutions of 5x² + 5x - 5 = 0?

The solutions of 5x² + 5x - 5 = 0 are x = (-1 + √5)/2 or x = (-1 - √5)/2, that is x ≈ 0.61803399 and x ≈ -1.618034.

Does 5x² + 5x - 5 = 0 factor?

Not over the integers, because the discriminant 125 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² + 5x - 5?

(-1/2, -25/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -1, product = c/a = -1.

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    Solve 5x² + 5x - 5 = 0: x = (-1 + √5)/2 or x = (-1 - √5)/2 (steps) | WordGPT