Solve 5x² + 5x - 4 = 0
The solutions of 5x² + 5x - 4 = 0 are x = (-5 + √105)/10 or x = (-5 - √105)/10, that is x ≈ 0.52469508 and x ≈ -1.5246951.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 5, c = -4.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ 0.52469508 and x ≈ -1.5246951.
- 7
Check numerically: for x ≈ 0.52469508 the left side is -4.4408921e-16 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ 5x^2 + 5x - 4 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{105}}{10},\ \frac{-5 - \sqrt{105}}{10} \]
\[ 5x^2 + 5x - 4 = 0 \]
\[ D = 5^2 - 4\cdot5\cdot(-4) = 25 + 80 = 105 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{105}}{10} \]
\[ x = \frac{-5 + \sqrt{105}}{10}\quad\text{or}\quad x = \frac{-5 - \sqrt{105}}{10} \]The parabola y = 5x² + 5x - 4
| x | y |
|---|---|
| -3.5 | 39.75 |
| -2.5 | 14.75 |
| -1.5 | -0.25 |
| -0.5 | -5.25 |
| 0.5 | -0.25 |
| 1.5 | 14.75 |
| 2.5 | 39.75 |
Questions
What are the solutions of 5x² + 5x - 4 = 0?
The solutions of 5x² + 5x - 4 = 0 are x = (-5 + √105)/10 or x = (-5 - √105)/10, that is x ≈ 0.52469508 and x ≈ -1.5246951.
Does 5x² + 5x - 4 = 0 factor?
Not over the integers, because the discriminant 105 is not a perfect square. Use the quadratic formula.
What is the vertex of y = 5x² + 5x - 4?
(-1/2, -21/4). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -1, product = c/a = -4/5.