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Solve 5x² + 12x + 3 = 0

The solutions of 5x² + 12x + 3 = 0 are x = (-6 + √21)/5 or x = (-6 - √21)/5, that is x ≈ -0.28348486 and x ≈ -2.1165151.

x² +x += 0
5x2+12x+3=0⇒x=−6+215, −6−2155x^2 + 12x + 3 = 0 \Rightarrow x = \frac{-6 + \sqrt{21}}{5},\ \frac{-6 - \sqrt{21}}{5}
Discriminant D = 84 · x ≈ -0.283485, -2.11652

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 5x² + 12x + 3-4-3-2-112-101020304050x = -0.28348486x = -2.1165151vertexy = 5x² + 12x + 3
Graph of y = 5x² + 12x + 3. The curve crosses the x-axis at x = -0.28348486 and x = -2.1165151; the vertex is at (-1.2, -4.2).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 12, c = 3.

    5x2+12x+3=05x^2 + 12x + 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=122−4⋅5⋅3=144−60=84D = 12^2 - 4\cdot5\cdot3 = 144 - 60 = 84
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−12±8410x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{84}}{10}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−6+215orx=−6−215x = \frac{-6 + \sqrt{21}}{5}\quad\text{or}\quad x = \frac{-6 - \sqrt{21}}{5}
  6. 6

    As decimals: x ≈ -0.28348486 and x ≈ -2.1165151.

  7. 7

    Check numerically: for x ≈ -0.28348486 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ 5x^2 + 12x + 3 = 0\ \Rightarrow\ x = \frac{-6 + \sqrt{21}}{5},\ \frac{-6 - \sqrt{21}}{5} \]
\[ 5x^2 + 12x + 3 = 0 \]
\[ D = 12^2 - 4\cdot5\cdot3 = 144 - 60 = 84 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{84}}{10} \]
\[ x = \frac{-6 + \sqrt{21}}{5}\quad\text{or}\quad x = \frac{-6 - \sqrt{21}}{5} \]

The parabola y = 5x² + 12x + 3

xy
-4.240.8
-3.215.8
-2.20.8
-1.2-4.2
-0.20.8
0.815.8
1.840.8

Questions

What are the solutions of 5x² + 12x + 3 = 0?

The solutions of 5x² + 12x + 3 = 0 are x = (-6 + √21)/5 or x = (-6 - √21)/5, that is x ≈ -0.28348486 and x ≈ -2.1165151.

Does 5x² + 12x + 3 = 0 factor?

Not over the integers, because the discriminant 84 is not a perfect square. Use the quadratic formula.

What is the vertex of y = 5x² + 12x + 3?

(-6/5, -21/5). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -12/5, product = c/a = 3/5.

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    Solve 5x² + 12x + 3 = 0: x = (-6 + √21)/5 or x = (-6 - √21)/5 (steps) | WordGPT