Solve 5x² + 12x + 2 = 0
The solutions of 5x² + 12x + 2 = 0 are x = (-6 + √26)/5 or x = (-6 - √26)/5, that is x ≈ -0.1801961 and x ≈ -2.2198039.
Change a, b or c (whole numbers, a not 0) and the exact solutions follow.
How to work it out
- 1
Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 5, b = 12, c = 2.
- 2
Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.
- 3
D is positive, so there are two different real solutions.
- 4
The quadratic formula works for every quadratic:
- 5
Simplify (pull the square out of the root) to get the solutions:
- 6
As decimals: x ≈ -0.1801961 and x ≈ -2.2198039.
- 7
Check numerically: for x ≈ -0.1801961 the left side is -4.4408921e-16 (zero up to rounding) ✓
LaTeX source of the formulas on this page
\[ 5x^2 + 12x + 2 = 0\ \Rightarrow\ x = \frac{-6 + \sqrt{26}}{5},\ \frac{-6 - \sqrt{26}}{5} \]
\[ 5x^2 + 12x + 2 = 0 \]
\[ D = 12^2 - 4\cdot5\cdot2 = 144 - 40 = 104 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-12 \pm \sqrt{104}}{10} \]
\[ x = \frac{-6 + \sqrt{26}}{5}\quad\text{or}\quad x = \frac{-6 - \sqrt{26}}{5} \]The parabola y = 5x² + 12x + 2
| x | y |
|---|---|
| -4.2 | 39.8 |
| -3.2 | 14.8 |
| -2.2 | -0.2 |
| -1.2 | -5.2 |
| -0.2 | -0.2 |
| 0.8 | 14.8 |
| 1.8 | 39.8 |
Questions
What are the solutions of 5x² + 12x + 2 = 0?
The solutions of 5x² + 12x + 2 = 0 are x = (-6 + √26)/5 or x = (-6 - √26)/5, that is x ≈ -0.1801961 and x ≈ -2.2198039.
Does 5x² + 12x + 2 = 0 factor?
Not over the integers, because the discriminant 104 is not a perfect square. Use the quadratic formula.
What is the vertex of y = 5x² + 12x + 2?
(-6/5, -26/5). The parabola opens upwards, so this is the minimum.
What are the sum and product of the roots?
Sum = −b/a = -12/5, product = c/a = 2/5.