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Solve 4x² - 3x + 9 = 0

4x² - 3x + 9 = 0 has no real solutions. The two complex solutions are x = (3 + 3√15 i)/8 and x = (3 - 3√15 i)/8.

x² +x += 0
4x2−3x+9=0⇒x=3+315 i8, 3−315 i8 (complex)4x^2 - 3x + 9 = 0 \Rightarrow x = \frac{3 + 3\sqrt{15}\, i}{8},\ \frac{3 - 3\sqrt{15}\, i}{8}\ \text{(complex)}
Discriminant D = -135

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 4x² - 3x + 9-3-2-1123410203040506070vertexy = 4x² - 3x + 9
Graph of y = 4x² - 3x + 9. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0.375, 8.4375).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 4, b = -3, c = 9.

    4x2−3x+9=04x^2 - 3x + 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−3)2−4⋅4⋅9=9−144=−135D = (-3)^2 - 4\cdot4\cdot9 = 9 - 144 = -135
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=3±−1358x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-135}}{8}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=3+315 i8orx=3−315 i8x = \frac{3 + 3\sqrt{15}\, i}{8}\quad\text{or}\quad x = \frac{3 - 3\sqrt{15}\, i}{8}
LaTeX source of the formulas on this page
\[ 4x^2 - 3x + 9 = 0\ \Rightarrow\ x = \frac{3 + 3\sqrt{15}\, i}{8},\ \frac{3 - 3\sqrt{15}\, i}{8} \]
\[ 4x^2 - 3x + 9 = 0 \]
\[ D = (-3)^2 - 4\cdot4\cdot9 = 9 - 144 = -135 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{3 \pm \sqrt{-135}}{8} \]
\[ x = \frac{3 + 3\sqrt{15}\, i}{8}\quad\text{or}\quad x = \frac{3 - 3\sqrt{15}\, i}{8} \]

The parabola y = 4x² - 3x + 9

xy
-2.62544.4375
-1.62524.4375
-0.62512.4375
0.3758.4375
1.37512.4375
2.37524.4375
3.37544.4375

Questions

What are the solutions of 4x² - 3x + 9 = 0?

4x² - 3x + 9 = 0 has no real solutions. The two complex solutions are x = (3 + 3√15 i)/8 and x = (3 - 3√15 i)/8.

Does 4x² - 3x + 9 = 0 factor?

Not over the integers, because the discriminant -135 is negative. Use the quadratic formula.

What is the vertex of y = 4x² - 3x + 9?

(3/8, 135/16). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 3/4, product = c/a = 9/4.

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