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Solve 3x² - x + 9 = 0

3x² - x + 9 = 0 has no real solutions. The two complex solutions are x = (1 + √107 i)/6 and x = (1 - √107 i)/6.

x² +x += 0
3x2−x+9=0⇒x=1+107 i6, 1−107 i6 (complex)3x^2 - x + 9 = 0 \Rightarrow x = \frac{1 + \sqrt{107}\, i}{6},\ \frac{1 - \sqrt{107}\, i}{6}\ \text{(complex)}
Discriminant D = -107

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² - x + 9-3-2-11234102030405060vertexy = 3x² - x + 9
Graph of y = 3x² - x + 9. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (0.16666667, 8.9166667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = -1, c = 9.

    3x2−x+9=03x^2 - x + 9 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−1)2−4⋅3⋅9=1−108=−107D = (-1)^2 - 4\cdot3\cdot9 = 1 - 108 = -107
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=1±−1076x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{-107}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=1+107 i6orx=1−107 i6x = \frac{1 + \sqrt{107}\, i}{6}\quad\text{or}\quad x = \frac{1 - \sqrt{107}\, i}{6}
LaTeX source of the formulas on this page
\[ 3x^2 - x + 9 = 0\ \Rightarrow\ x = \frac{1 + \sqrt{107}\, i}{6},\ \frac{1 - \sqrt{107}\, i}{6} \]
\[ 3x^2 - x + 9 = 0 \]
\[ D = (-1)^2 - 4\cdot3\cdot9 = 1 - 108 = -107 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{1 \pm \sqrt{-107}}{6} \]
\[ x = \frac{1 + \sqrt{107}\, i}{6}\quad\text{or}\quad x = \frac{1 - \sqrt{107}\, i}{6} \]

The parabola y = 3x² - x + 9

xy
-2.833335.916067
-1.833320.916267
-0.833311.916467
0.16678.9166667
1.166711.916867
2.166720.917067
3.166735.917267

Questions

What are the solutions of 3x² - x + 9 = 0?

3x² - x + 9 = 0 has no real solutions. The two complex solutions are x = (1 + √107 i)/6 and x = (1 - √107 i)/6.

Does 3x² - x + 9 = 0 factor?

Not over the integers, because the discriminant -107 is negative. Use the quadratic formula.

What is the vertex of y = 3x² - x + 9?

(1/6, 107/12). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 1/3, product = c/a = 3.

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