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Solve 3x² + 8x + 7 = 0

3x² + 8x + 7 = 0 has no real solutions. The two complex solutions are x = (-4 + √5 i)/3 and x = (-4 - √5 i)/3.

x² +x += 0
3x2+8x+7=0⇒x=−4+5 i3, −4−5 i3 (complex)3x^2 + 8x + 7 = 0 \Rightarrow x = \frac{-4 + \sqrt{5}\, i}{3},\ \frac{-4 - \sqrt{5}\, i}{3}\ \text{(complex)}
Discriminant D = -20

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = 3x² + 8x + 7-5-4-3-2-1121020304050vertexy = 3x² + 8x + 7
Graph of y = 3x² + 8x + 7. The curve never reaches the x-axis, which is why there are no real solutions; the vertex is at (-1.3333333, 1.6666667).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 3, b = 8, c = 7.

    3x2+8x+7=03x^2 + 8x + 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=82−4⋅3⋅7=64−84=−20D = 8^2 - 4\cdot3\cdot7 = 64 - 84 = -20
  3. 3

    D is negative, so there are no real solutions; the two solutions are complex numbers.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−8±−206x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{-20}}{6}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−4+5 i3orx=−4−5 i3x = \frac{-4 + \sqrt{5}\, i}{3}\quad\text{or}\quad x = \frac{-4 - \sqrt{5}\, i}{3}
LaTeX source of the formulas on this page
\[ 3x^2 + 8x + 7 = 0\ \Rightarrow\ x = \frac{-4 + \sqrt{5}\, i}{3},\ \frac{-4 - \sqrt{5}\, i}{3} \]
\[ 3x^2 + 8x + 7 = 0 \]
\[ D = 8^2 - 4\cdot3\cdot7 = 64 - 84 = -20 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-8 \pm \sqrt{-20}}{6} \]
\[ x = \frac{-4 + \sqrt{5}\, i}{3}\quad\text{or}\quad x = \frac{-4 - \sqrt{5}\, i}{3} \]

The parabola y = 3x² + 8x + 7

xy
-4.333328.666067
-3.333313.666267
-2.33334.6664667
-1.33331.6666667
-0.33334.6668667
0.666713.667067
1.666728.667267

Questions

What are the solutions of 3x² + 8x + 7 = 0?

3x² + 8x + 7 = 0 has no real solutions. The two complex solutions are x = (-4 + √5 i)/3 and x = (-4 - √5 i)/3.

Does 3x² + 8x + 7 = 0 factor?

Not over the integers, because the discriminant -20 is negative. Use the quadratic formula.

What is the vertex of y = 3x² + 8x + 7?

(-4/3, 5/3). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -8/3, product = c/a = 7/3.

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