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Solve x² - 4x - 4 = 0

The solutions of x² - 4x - 4 = 0 are x = 2 + 2√2 or x = 2 - 2√2, that is x ≈ 4.8284271 and x ≈ -0.82842712.

x² +x += 0
x2−4x−4=0⇒x=2+22, 2−22x^2 - 4x - 4 = 0 \Rightarrow x = 2 + 2\sqrt{2},\ 2 - 2\sqrt{2}
Discriminant D = 32 · x ≈ 4.82843, -0.828427

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² - 4x - 4-2246-10-55101520x = 4.8284271x = -0.82842712vertexy = x² - 4x - 4
Graph of y = x² - 4x - 4. The curve crosses the x-axis at x = 4.8284271 and x = -0.82842712; the vertex is at (2, -8).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -4, c = -4.

    x2−4x−4=0x^2 - 4x - 4 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−4)2−4⋅1⋅(−4)=16+16=32D = (-4)^2 - 4\cdot1\cdot(-4) = 16 + 16 = 32
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=4±322x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{32}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=2+22orx=2−22x = 2 + 2\sqrt{2}\quad\text{or}\quad x = 2 - 2\sqrt{2}
  6. 6

    As decimals: x ≈ 4.8284271 and x ≈ -0.82842712.

  7. 7

    Check numerically: for x ≈ 4.8284271 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 - 4x - 4 = 0\ \Rightarrow\ x = 2 + 2\sqrt{2},\ 2 - 2\sqrt{2} \]
\[ x^2 - 4x - 4 = 0 \]
\[ D = (-4)^2 - 4\cdot1\cdot(-4) = 16 + 16 = 32 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{32}}{2} \]
\[ x = 2 + 2\sqrt{2}\quad\text{or}\quad x = 2 - 2\sqrt{2} \]

The parabola y = x² - 4x - 4

xy
-11
0-4
1-7
2-8
3-7
4-4
51

Questions

What are the solutions of x² - 4x - 4 = 0?

The solutions of x² - 4x - 4 = 0 are x = 2 + 2√2 or x = 2 - 2√2, that is x ≈ 4.8284271 and x ≈ -0.82842712.

Does x² - 4x - 4 = 0 factor?

Not over the integers, because the discriminant 32 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² - 4x - 4?

(2, -8). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 4, product = c/a = -4.

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    Solve x² - 4x - 4 = 0: x = 2 + 2√2 or x = 2 - 2√2 (steps) | WordGPT