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Solve x² - 4x - 3 = 0

The solutions of x² - 4x - 3 = 0 are x = 2 + √7 or x = 2 - √7, that is x ≈ 4.6457513 and x ≈ -0.64575131.

x² +x += 0
x2−4x−3=0⇒x=2+7, 2−7x^2 - 4x - 3 = 0 \Rightarrow x = 2 + \sqrt{7},\ 2 - \sqrt{7}
Discriminant D = 28 · x ≈ 4.64575, -0.645751

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

Graph of y = x² - 4x - 3-3-2-11234567-10-55101520x = 4.6457513x = -0.64575131vertexy = x² - 4x - 3
Graph of y = x² - 4x - 3. The curve crosses the x-axis at x = 4.6457513 and x = -0.64575131; the vertex is at (2, -7).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = -4, c = -3.

    x2−4x−3=0x^2 - 4x - 3 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=(−4)2−4⋅1⋅(−3)=16+12=28D = (-4)^2 - 4\cdot1\cdot(-3) = 16 + 12 = 28
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=4±282x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{28}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=2+7orx=2−7x = 2 + \sqrt{7}\quad\text{or}\quad x = 2 - \sqrt{7}
  6. 6

    As decimals: x ≈ 4.6457513 and x ≈ -0.64575131.

  7. 7

    Check numerically: for x ≈ 4.6457513 the left side is 0 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 - 4x - 3 = 0\ \Rightarrow\ x = 2 + \sqrt{7},\ 2 - \sqrt{7} \]
\[ x^2 - 4x - 3 = 0 \]
\[ D = (-4)^2 - 4\cdot1\cdot(-3) = 16 + 12 = 28 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{4 \pm \sqrt{28}}{2} \]
\[ x = 2 + \sqrt{7}\quad\text{or}\quad x = 2 - \sqrt{7} \]

The parabola y = x² - 4x - 3

xy
-12
0-3
1-6
2-7
3-6
4-3
52

Questions

What are the solutions of x² - 4x - 3 = 0?

The solutions of x² - 4x - 3 = 0 are x = 2 + √7 or x = 2 - √7, that is x ≈ 4.6457513 and x ≈ -0.64575131.

Does x² - 4x - 3 = 0 factor?

Not over the integers, because the discriminant 28 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² - 4x - 3?

(2, -7). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = 4, product = c/a = -3.

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    Solve x² - 4x - 3 = 0: x = 2 + √7 or x = 2 - √7 (steps) | WordGPT