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Solve x² + 6x - 7 = 0

The solutions of x² + 6x - 7 = 0 are x = 1 or x = -7.

x² +x += 0
x2+6x−7=0⇒x=1, −7x^2 + 6x - 7 = 0 \Rightarrow x = 1,\ -7
Discriminant D = 64 · x ≈ 1, -7

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = x² + 6x - 7-8-6-4-22-20-101020x = 1x = -7vertexy = x² + 6x - 7
Graph of y = x² + 6x - 7. The curve crosses the x-axis at x = 1 and x = -7; the vertex is at (-3, -16).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 6, c = -7.

    x2+6x−7=0x^2 + 6x - 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=62−4⋅1⋅(−7)=36+28=64D = 6^2 - 4\cdot1\cdot(-7) = 36 + 28 = 64
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    Method 1, factoring. The roots are rational, so the left side factors:

    (x−1)(x+7)=0\left(x - 1\right)\left(x + 7\right) = 0
  5. 5

    A product is zero when one of its factors is zero, so set each factor equal to 0 and solve:

    x−1=0⇒x=1x+7=0⇒x=−7x - 1 = 0 \Rightarrow x = 1\qquad x + 7 = 0 \Rightarrow x = -7
  6. 6

    Method 2, The quadratic formula works for every quadratic:

    x=−b±D2a=−6±642x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{64}}{2}
  7. 7

    Simplify to get the solutions:

    x=1orx=−7x = 1\quad\text{or}\quad x = -7
  8. 8

    Check by putting x = 1 back in: a·x² + b·x + c = 1·(1) + 6·(1) + (-7) = 0 ✓

LaTeX source of the formulas on this page
\[ x^2 + 6x - 7 = 0\ \Rightarrow\ x = 1,\ -7 \]
\[ x^2 + 6x - 7 = 0 \]
\[ D = 6^2 - 4\cdot1\cdot(-7) = 36 + 28 = 64 \]
\[ \left(x - 1\right)\left(x + 7\right) = 0 \]
\[ x - 1 = 0 \Rightarrow x = 1\qquad x + 7 = 0 \Rightarrow x = -7 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-6 \pm \sqrt{64}}{2} \]
\[ x = 1\quad\text{or}\quad x = -7 \]

The parabola y = x² + 6x - 7

xy
-6-7
-5-12
-4-15
-3-16
-2-15
-1-12
0-7

Questions

What are the solutions of x² + 6x - 7 = 0?

The solutions of x² + 6x - 7 = 0 are x = 1 or x = -7.

Does x² + 6x - 7 = 0 factor?

Yes: (x-1)(x+7) = 0.

What is the vertex of y = x² + 6x - 7?

(-3, -16). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -6, product = c/a = -7.

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