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Solve x² + 5x - 7 = 0

The solutions of x² + 5x - 7 = 0 are x = (-5 + √53)/2 or x = (-5 - √53)/2, that is x ≈ 1.1400549 and x ≈ -6.1400549.

x² +x += 0
x2+5x−7=0⇒x=−5+532, −5−532x^2 + 5x - 7 = 0 \Rightarrow x = \frac{-5 + \sqrt{53}}{2},\ \frac{-5 - \sqrt{53}}{2}
Discriminant D = 53 · x ≈ 1.14005, -6.14005

Change a, b or c (whole numbers, a not 0) and the exact solutions follow.

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Graph of y = x² + 5x - 7-8-6-4-22-101020x = 1.1400549x = -6.1400549vertexy = x² + 5x - 7
Graph of y = x² + 5x - 7. The curve crosses the x-axis at x = 1.1400549 and x = -6.1400549; the vertex is at (-2.5, -13.25).

How to work it out

  1. 1

    Write it in standard form a x² + b x + c = 0 and read off the coefficients: a = 1, b = 5, c = -7.

    x2+5x−7=0x^2 + 5x - 7 = 0
  2. 2

    Work out the discriminant D = b² − 4ac. Its sign tells you how many real solutions there are.

    D=52−4⋅1⋅(−7)=25+28=53D = 5^2 - 4\cdot1\cdot(-7) = 25 + 28 = 53
  3. 3

    D is positive, so there are two different real solutions.

  4. 4

    The quadratic formula works for every quadratic:

    x=−b±D2a=−5±532x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{53}}{2}
  5. 5

    Simplify (pull the square out of the root) to get the solutions:

    x=−5+532orx=−5−532x = \frac{-5 + \sqrt{53}}{2}\quad\text{or}\quad x = \frac{-5 - \sqrt{53}}{2}
  6. 6

    As decimals: x ≈ 1.1400549 and x ≈ -6.1400549.

  7. 7

    Check numerically: for x ≈ 1.1400549 the left side is -1.7763568e-15 (zero up to rounding) ✓

LaTeX source of the formulas on this page
\[ x^2 + 5x - 7 = 0\ \Rightarrow\ x = \frac{-5 + \sqrt{53}}{2},\ \frac{-5 - \sqrt{53}}{2} \]
\[ x^2 + 5x - 7 = 0 \]
\[ D = 5^2 - 4\cdot1\cdot(-7) = 25 + 28 = 53 \]
\[ x = \frac{-b \pm \sqrt{D}}{2a} = \frac{-5 \pm \sqrt{53}}{2} \]
\[ x = \frac{-5 + \sqrt{53}}{2}\quad\text{or}\quad x = \frac{-5 - \sqrt{53}}{2} \]

The parabola y = x² + 5x - 7

xy
-5.5-4.25
-4.5-9.25
-3.5-12.25
-2.5-13.25
-1.5-12.25
-0.5-9.25
0.5-4.25

Questions

What are the solutions of x² + 5x - 7 = 0?

The solutions of x² + 5x - 7 = 0 are x = (-5 + √53)/2 or x = (-5 - √53)/2, that is x ≈ 1.1400549 and x ≈ -6.1400549.

Does x² + 5x - 7 = 0 factor?

Not over the integers, because the discriminant 53 is not a perfect square. Use the quadratic formula.

What is the vertex of y = x² + 5x - 7?

(-5/2, -53/4). The parabola opens upwards, so this is the minimum.

What are the sum and product of the roots?

Sum = −b/a = -5, product = c/a = -7.

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    Solve x² + 5x - 7 = 0: x = (-5 + √53)/2 or x = (-5 - √53)/2 (steps) | WordGPT